How the following paris of points are placed w.r.t the line 3x-8y-7=0? `(i) (-3,-4) and (1,2) " " (ii) (-1,-1) and (3,7)`
How the following paris of points are placed w.r.t the line 3x-8y-7=0?
`(i) (-3,-4) and (1,2) " " (ii) (-1,-1) and (3,7)`
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Correct Answer - (i) points are on opposite sides of the line
(ii) points are on same side of the line
We have L(x,y) = 3x-8y-7
`(i) L(-3,-4)=3(-3)-8(-4)-7 = 16 gt 0`
`L(1,2)=3(1)-8(2)-7 = -20 lt 0`
So, points are on opposite sides of the line.
(ii) L(-1,-1) = 3(-1)-8(-1)-7 `=-2 lt 0`
L (3,7) = 3(3)-8(7)-7 `=-54 lt 0`
So, points are on the same side of the line.
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