`Ifx=int_c^(sint)sin^(-1)z dz ,y=int_k^(sqrt(t))(sinz^2)/zdz ,t h e n(dy)/(dx)i se q u a lto` `(tant)/(2t)` (b) `(tant)/(t^2)` `t/(2t^2)` (d) `(t a tt
`Ifx=int_c^(sint)sin^(-1)z dz ,y=int_k^(sqrt(t))(sinz^2)/zdz ,t h e n(dy)/(dx)i se q u a lto`
`(tant)/(2t)`
(b) `(tant)/(t^2)`
`t/(2t^2)`
(d) `(t a tt^2)/(2t^2)`
A. `(tant)/(2t)`
B. `(tant)/(t^(2))`
C. `(tan t)/(2t^(2))`
D. `(tan t^(2))/(2t^(2))`
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Correct Answer - C
`(dx)/(dt)=sin^(-1)(sint)cost=tcost`
and `(dy)/(dt)=(sint)/(sqrt(t)) . 1/(2sqrt(t))= (sin t)/(2t)` or `(dy)/(dx)= (sint)/(2t . t cost)=(tant)/(2t^(2))`
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