The "mole"s of electrons required to deposit 1 gm equivalent aluminium (at wt. =27) from a solution of aluminium chloride will be:
A. 3
B. 1
C. 4
D. 2

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1 Answers

Correct Answer - A
`Al^(3+)+3e^(-)toAl` So mole of `e^(-)=3`

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