Calculate the cell emf and `triangle_(r)G^(@)` for the cell reactin at `25^(@)C` `Zn(s)|Zn^(2+)(0.1M)||Cd^(2+)(0.01M)|Cd(s)` (given `E_(Zn^(2+)//Zn)^(

Question

Calculate the cell emf and `triangle_(r)G^(@)` for the cell reactin at `25^(@)C` `Zn(s)|Zn^(2+)(0.1M)||Cd^(2+)(0.01M)|Cd(s)` (given `E_(Zn^(2+)//Zn)^(

Calculate the cell emf and `triangle_(r)G^(@)` for the cell reactin at `25^(@)C`
`Zn(s)|Zn^(2+)(0.1M)||Cd^(2+)(0.01M)|Cd(s)`
(given `E_(Zn^(2+)//Zn)^(@)=-0.763V,E_(Cd^(2+)//Cd)^(@)=-0.403V`
`1F=96500Cmol^(-1),R=8.314JK^(-1)mol^(-1)]`

Monjur Alahi

9 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

`E_(cell)^(@)=E_("cathode")^(@)-E_("anode")^(@)=-0.403-(-0.763)=0.360V`
`E_(cell)=E_(cell)^(@)-(0.059)/(n)log(([Zn^(2+)(aq)])/([Cd^(2+)(aq)]))`
`E_(cell)=0.36-(0.059)/(2)log((0.1)/(0.01))=0.33V`
`triangle_(r)G^(@)=-nFE_(cell)^(@)=-2xx96500xx0.36=-69480Jmol^(-1)=-69.48kJmol^(-1)`

9 views Answered 2023-02-05 15:29