Write the nearest equation and calculate the e.m.f. of the following cell at 298 K
`Cu(s)|Cu^(2+)(0.130M)||Ag^(+)(1.00xx10^(-4)M)|Ag(s)`
Given `:E_(Cu^(2+)//Cu)^(@)=0.34V` and `E_(Ag^(+)//Ag)^(@)=+0.80V`

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1 Answers

`Cu+2Ag^(+)toCu^(2+)+2Ag`
the nearest equation for the cell `(n=2)` is
`E_(cell)=(E_(Ag^(+)//Ag)^(@)-E_(Cu^(2+)//Ag)^(@))-(0.059)/(2)log(([Cu^(2+)(aq)])/([Ag^(+)(aq)]))`
`E_(cell)=(+0.8-0.34)-(0.059)/(2)log((0.130)/((10^(-4))^(2)))`
`=0.46-(0.059)/(2)xx7.1139`
`=0.46-0.21=0.25V`

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