The conductivity of saturated solution of `BaSO_(4)` is `3.06xx10^(-6) ohm^(-1) cm^(-1)` and its equivalent conductance is 1.53 `ohm^(-1) cm^(2) "equi
The conductivity of saturated solution of `BaSO_(4)` is `3.06xx10^(-6) ohm^(-1) cm^(-1)` and its equivalent conductance is 1.53 `ohm^(-1) cm^(2) "equiv"^(-1)`. The `K_(sp)` for `BaSO_(4)` will be:
A. `4xx10^(-12)`
B. `2.5xx10^(-13)`
C. `25xx10^(-9)`
D. `10^(-6)`
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Correct Answer - D
`1.53=(1000xx3.06xx10^(-6))/("normality")`
normality `=2xx10^(-3)M`
molarity `=(2xx10^(-3))/(2)=10^(-3)M`
`K_(SP)=10^(-6)M`
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