Using the information in the preceding problem, calculate the solubility product of Agl in water at `25^(@)C` `[E_((Ag^(+),Ag))^(@)=+0.799`volt]
A. `1.97xx10^(-17)`
B. `8.43xx10^(-17)`
C. `1.79xx10^(-17)`
D. `9.17xx10^(-17)`

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1 Answers

Correct Answer - B
`E_(Ag|AgI|I^(-))^(0)=E_(Ag^(+)|Ag)^(0)-(0.0591)/(1)log((1)/(K_(SP))`
`-0.151=0.799-(0.0591)/(1)log((1)/(K_(sp))implies0.0591logK_(SP)=-0.151-0.799`
`logK_(SP)=-16.074impliesK_(SP)=8.43xx10^(-17)`

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