For a perfectly crystaline solid `C_(p.m)=aT^(3)` , where `a` is constant. If `C_(p.m)` is `0.42J//K-mol` at `10 K`, molar entropy at `10 K` is:

Question

For a perfectly crystaline solid `C_(p.m)=aT^(3)` , where `a` is constant. If `C_(p.m)` is `0.42J//K-mol` at `10 K`, molar entropy at `10 K` is:

For a perfectly crystaline solid `C_(p.m)=aT^(3)` , where `a` is constant. If `C_(p.m)` is `0.42J//K-mol` at `10 K`, molar entropy at `10 K` is:
A. `0.42 J//K-mol`
B. `0.14 J//K-mol`
C. `4.2 J//K-mol`
D. Zero

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`S_(m)=underset(0)overset(10)int(C_(p.m))/(T) dT-underset(0)overset(10)intaT^(2)=(a)/(3)[10^(3)-0]=(0.42)/(3)=0.14J//K-mol`

4 views Answered 2023-02-05 15:29