In an LCR circuit, the capacitance is made one-fourth, when in resonance. Then what should be the change in inductance, so that the circuit remains in resonance?
A. `4` times
B. `1//4` times
C. `8` times
D. `2` times

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1 Answers

Correct Answer - A
At resonance `omegaL=1/(omegaC) rArr l prop 1/C`.

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