`A` drop of water of volume `V` is pressed between the two glass plates so as to spread to an area. `A`. If `T` is the surface tension, the normal for
`A` drop of water of volume `V` is pressed between the two glass plates so as to spread to an area. `A`. If `T` is the surface tension, the normal force required to separate the glass plates is
A. `(TA^(2))/(V)`
B. `(2TA^(2))/(V)`
C. `(4TA^(2))/(V)`
D. `(TA^(2))/(2V)`
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Correct Answer - B
Force required to separate the glass plates `F=(2AT)/(t) xx (A)/(A) = (2TA^(2))/((Axxt)) = (2TA^(2))/(V)`
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