The radii of two soap bubbles are `R_(1)` and `R_(2)` respectively. The ratio of masses of air in them will be
The radii of two soap bubbles are `R_(1)` and `R_(2)` respectively. The ratio of masses of air in them will be
A. `(R_(1)^(3))/(R_(2)^(3))`
B. `(R_(2)^(3))/(R_(1)^(3))`
C. `((P+(4T)/(R_(1)))/(P+(4T)/(R_(2))))(R_(1)^(3))/(R_(2)^(3))`
D. `((P+(4T)/(R_(2)))/(P+(4T)/(R_(1))))(R_(2)^(3))/(R_(1)^(3))`
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Correct Answer - C
From `PV = muRT`.
At a given temperature, the ratio masses of air
`(mu_(1))/(mu_(2))=(P_(1)V_(1))/(P_(2)V_(2))= ((P+(4T)/(R_(1))))/((P+(4T)/(R_(2))))((4)/(3)piR_(1)^(3))/((4)/(3)piR_(2)^(3))=((P+(4T)/R_(1)))/((P+(4T)/(R_(2))))(R_(1)^(3))/(R_(2)^(3))`
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