The thermo e.m.f. E in volts of a certain thermocouple is found to vary with temperature difference q in `.^(@)C` between the two junctions according to the relation `E=30 theta-(theta^(2))/(15)`
The neutral temperature for the thermo-couple will be:-
A. `400^(@)C`
B. `225^ (@)C`
C. `30^(@)C`
D. `450^(@)C`

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1 Answers

At neutral temperature `(dE)/(dtheta)=0`
so `30-(2thetan)/(15) =0rArrtheta_(n)=225^(@)C`

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