`(s in5theta+s in2theta-s intheta)/(cos5theta+2cos3theta+2cos^2theta+costheta)` is equal to `t a ntheta` b. `costheta` c.`cottheta` d. none of these

Question

`(s in5theta+s in2theta-s intheta)/(cos5theta+2cos3theta+2cos^2theta+costheta)` is equal to `t a ntheta` b. `costheta` c.`cottheta` d. none of these

`(s in5theta+s in2theta-s intheta)/(cos5theta+2cos3theta+2cos^2theta+costheta)` is equal to `t a ntheta` b. `costheta` c.`cottheta` d. none of these
A. `tan theta`
B. `cos theta`
C. `cot theta`
D. none of these

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

If `s intheta+sin^2theta1=1,` then prove that `cos^(12)theta+3cos^8theta+cos^6theta-1=0` Given that `s i lntheta=1-sin^2theta=1-sin^2theta=cos^2theta`

2 Answers 5 Views

`tan(pi/4+1/2cos^-1x)+tan(pi/4-1/2cos^-1x)`, `x!=0` is equal to

2 Answers 4 Views

If `tan^(-1)(sin^2theta-2sintheta+3)+cot^(-1)(5^sec^(2y)+1)=pi/2,` then value of `cos^2theta-sintheta` is equal to 0 (b) `-1` (c) `1` (d) none of thes

2 Answers 4 Views

If the points `(1,1):(0,sec^2theta);` and `(cos e c^2theta,0)` are collinear, then find the value of `theta`

2 Answers 8 Views

If `x=cos e ctheta-sinthetaa n dy=cos e c^ntheta-sin^ntheta,` then show that `(x^2+4)((dy)/(dx))^2=n^2(y^2+4)dot`

2 Answers 5 Views

The value of the integral `int((1-costheta)^(2/7))/((1+costheta)^(9/7))dthetai s` `7/(11)(t a ntheta/2)^((11)/7)+C` (b) `7/(11)(costheta/2)^((11)/7)+C

2 Answers 4 Views

If `sec^4theta+sec^2theta=10+tan^4theta+tan^2theta", then "sin^2theta=`

2 Answers 6 Views

Range of `f(theta)=cos^2theta(cos^2theta+1)+2 sin^2theta` is

2 Answers 5 Views

If `cottheta+tantheta=xand sectheta-costheta=y`, then

2 Answers 4 Views

If `pcos e ctheta+qcottheta=2` and `p^2cos e c^2theta-q^2theta=5` then the value of `sqrt(81 p^(-2))` is________

2 Answers 4 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

LHS`=(2sin 2 theta cos 3 theta+sin 2 theta)/(2 cos 3 theta,cos 2 theta+2 cos 3 theta+2 cos ^(2)theta)=(sin 2theta[2 cos 3 theta+1])/(2[cos 3 theta(cos 2 theta+1)+(cos ^(2)theta)])`
`=(sin2 theta[2 cos 3 theta+1])/(2[cos 3 theta(2 cos ^(2)theta)+cos^(2)theta])=(sin2 theta(2 cos 3 theta+1))/(2 cos^(2)theta(2 cos 3 theta+1))=tan theta`