The equilibrium constants for the reaction, `A_2hArr2A` A at `500K and 700K` are `1xx10^(-10)` and `1xx10^(-5)`. The given reaction is

Question

The equilibrium constants for the reaction, `A_2hArr2A` A at `500K and 700K` are `1xx10^(-10)` and `1xx10^(-5)`. The given reaction is

The equilibrium constants for the reaction, `A_2hArr2A` A at `500K and 700K` are `1xx10^(-10)` and `1xx10^(-5)`. The given reaction is
A. exothermic
B. slow
C. endothermic
D. fast

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Related Questions

Assertion: In rate law, unlike in expression for equilibrium constants, the exponents for the concentration donot necessarily match the stoichometric

2 Answers 6 Views

One mole of a real gas is subjected to a process from (2 bar , 30 lit ., 300k) to (2 bar , 40 , lit ., 500K) Given :`C_(v)=25 J//"mole"/K` `C_(p)=40 J

2 Answers 4 Views

Equilibrium constant for the given reaction is `K=10^(20)` at temperature 300 K `A(s)+2B(aq.)hArr2C(s)+D(aq.) K=10^20` The equilibrium conc. of B star

2 Answers 9 Views

The equilibrium constants for amino acids are given in terms of succesive ionization constants of the protonated form.For example, equilibrium constat

2 Answers 5 Views

The equilibrium constants of the following are

2 Answers 5 Views

In a reversible chemical reaction having two reactants in equilibrium, if the concentration of the reactants are doubled then the equilibrium constant

2 Answers 5 Views

If density of vapours of a substance of molar mass `18 gm at 1 atm` pressure and`500K` is `0.36 kg m^(-3)`, then calculate the value of `Z` for the va

2 Answers 5 Views

For the reaction `2NO(g)+O_(2)(g)to2NO_(2)g` Calculate `DeltaG` at 700K when enthalpy and entropy changes are `-113.0kJ" "mol^(-1) and `-145J" "K^(-1)

2 Answers 5 Views

For a reaction taking place in a container in equilibrium with its surroundings, the effect of temperature on its equilibrium constant Kin terms of ch

2 Answers 5 Views

For the reaction at equilibrium: `A(g)+2B(g)hArrC(g)` Equilibrium constants as function of temperature are K at `300^(@)C 4xx10^(-4)` K at `450^(@)C 4

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
For the reaction.
`A-2hArr2A`
`K=([A])^2/([A_2])`
The value of equilibrium constant is very less and hence, the product concentration is also very less. So, the reaction is slow.

5 views Answered 2023-02-05 15:29