The angle between the two vectors `vecA=3hati+4hatj+5hatk` and `vecB=3hati+4hatj-5hatk` will be :
The angle between the two vectors `vecA=3hati+4hatj+5hatk` and `vecB=3hati+4hatj-5hatk` will be :
A. zero
B. `180^(@)`
C. `90^(@)`
D. `45^(@)`
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Correct Answer - C
`cos theta=(vecA.vecB)/(AB)=((3hati+4hatj)+5hatk)((3hati+4hatj-5hatk))/((5sqrt(2))(5sqrt(2)))=0`
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