Compound `I` and `II` can be distinguished by using reagent. `underset("4-Hydroxy-4-methylpent-2-enoic acid")((I))` " " `underset("5-Hydroxypent-2-yno

Question

Compound `I` and `II` can be distinguished by using reagent. `underset("4-Hydroxy-4-methylpent-2-enoic acid")((I))` " " `underset("5-Hydroxypent-2-yno

Compound `I` and `II` can be distinguished by using reagent.
`underset("4-Hydroxy-4-methylpent-2-enoic acid")((I))` " " `underset("5-Hydroxypent-2-ynoic acid")((II))`
A. `NaHCO_(3)`
B. `Br_(2)//H_(2)O`
C. `HCl//ZnCl_(2)` (anhydrous)
D. `Cu_(2)Cl_(2)//NH_(4)OH`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - C
`underset((I))(underset(HOOC)underset(|)(HC)=underset(H)underset(|)(C )-underset(OH)underset(|)overset(CH_(3))overset(|)(C )-CH_(3))` " " `underset((II))(underset(HOOC)underset(|)(C )-=C-CH_(2)-underset(OH)underset(|)(CH_(2)))`
`(I)` gives immediate turbidity by Lucas reagent and `(II)` does not give turbidity appriciably.