A unit vector parallel to the intersection of the planes `vecr.(hati-hatj+hatk)=5 andvecr.(2hati+hatj-3hatk)=4` is
A. `(2hati+5hatj-3hatk)/(sqrt38)`
B. `(2hati-5hatj+3hatk)/(sqrt38)`
C. `(-2hati-5hatj-3hatk)/(sqrt38)`
D. `(-2hati+5hatj-3hatk)/(sqrt38)`

5 views

1 Answers

Correct Answer - c
`hata=pm(vecn_(1)xxvecc_(2))/(|vecn_(1)xxvec n_(2)|)=pm(2hati+5hatj+3hatk)/(sqrt38)`
(where `vecn_(1)andvecn_(2)` are normal to the planes)

5 views

Related Questions