Atomic number of `Ag` is 4.7. in the same group, the atomic numbers of elements placed above and below `Ag` in Long form of periodic table will be:

Question

Atomic number of `Ag` is 4.7. in the same group, the atomic numbers of elements placed above and below `Ag` in Long form of periodic table will be:

Atomic number of `Ag` is 4.7. in the same group, the atomic numbers of elements placed above and below `Ag` in Long form of periodic table will be:
A. 26, 95
B. 39,79
C. 29,79
D. 39,65

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
Silver belongs to `V^(th)` period. So the atomic number of element placed above and below will be `47 - 18 = 29` and `47 +32 = 79` respectively.

4 views Answered 2023-02-05 15:29