Find the joint equation of the pair of lines which pass through the origin and are perpendicular to the lines represented the equation `y^2+3x y-6x+5y-14=0`

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1 Answers

Homogeneous part of the given equation is `y^(2)+3xy=0`.
So , component lines are `y=0and y+3x=0`.
Lines perpendicular to these lines are `x=0 and 3xy=0` .
So , combined equation of above lines is `x^(2)-3xy=0`.

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