The variance of first n natural number is:
The variance of first n natural number is:
A. `(n^(2)-1)/(12)`
B. `(n^(2)-1)/(6)`
C. `(n^(2)+1)/(6)`
D. `(n^(2)+1)/(12)`
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Correct Answer - A
Variance`=(SD)^(2)=(1)/(n)sumx^(2)-((sum x)/(n))^(2), (because overline(x)=(sum x)/(n))`
`=(n(n+1)(2n+1))/(6n)-((n(n+1))/(2n))^(2)=(n^(2)-1)/(12)`
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