PARAGRAPH A There are five students `S_1, S_2, S_3, S_4` and `S_5` in a music class and for them there are five seats `R_1, R_2, R_3, R_4` and `R_5` a

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PARAGRAPH A There are five students `S_1, S_2, S_3, S_4` and `S_5` in a music class and for them there are five seats `R_1, R_2, R_3, R_4` and `R_5` a

PARAGRAPH A There are five students `S_1, S_2, S_3, S_4` and `S_5` in a music class and for them there are five seats `R_1, R_2, R_3, R_4` and `R_5` arranged in a row, where initially the seat `R_i` is allotted to the student `S_i , i=1, 2, 3, 4, 5` . But, on the examination day, the five students are randomly allotted five seats. (For Ques. No. 17 and 18) The probability that, on the examination day, the student `S_1` gets the previously allotted seat `R_1` , and NONE of the remaining students gets the seat previously allotted to him/her is `3/(40)` (b) `1/8` (c) `7/(40)` (d) `1/5`
A. `(3)/(40)`
B. `(1)/(8)`
C. `(7)/(40)`
D. `(1)/(5)`

Monjur Alahi

9 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
Total number of cases = `5!`
Since `S_(1)` gets seat `R_(1)` and none of the other gets previously allotted seat, we have derangement of 4 students. So, required probability
`=(4!(1-(1)/(1!)+(1)/(2!)-(1)/(3!)+(1)/(4!)))/(5!) = (9)/(120) = (3)/(40)`

9 views Answered 2023-02-05 15:29