A bag has 10 balls. Six ball are drawn in an attempt and replaced. Then another draw of 5 balls is made from the bag. The probability that exactly two

Question

A bag has 10 balls. Six ball are drawn in an attempt and replaced. Then another draw of 5 balls is made from the bag. The probability that exactly two

A bag has 10 balls. Six ball are drawn in an attempt and replaced. Then another draw of 5 balls is made from the bag. The probability that exactly two balls are common to both the draw is `5//21` b. `2//21` c. `7//21` d. `3//21`
A. `5//21`
B. `2//21`
C. `7//21`
D. `3//21`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
The total number of ways of making the second draw is `.^(10)C_(5)`.
The number of draws of 5 balls containing 2 balls common with first draw of 6 balls is `.^(6)C_(2).^(4)C_(3)`. Therefore, the probability is
`(.^(6)C_(2).^(4)C_(3))/(.^(10)C_(5) )= (5)/(21)`

5 views Answered 2023-02-05 15:29