In a `n-` sided regular polygon, the probability that the two diagonal chosen at random will intersect inside the polygon is `(2^n C_2)/(^(^(n C_(2-n)
In a `n-`
sided regular polygon, the probability that the two diagonal chosen at
random will intersect inside the polygon is
`(2^n C_2)/(^(^(n C_(2-n)))C_2)`
b. `(^(n(n-1))C_2)/(^(^(n C_(2-n)))C_2)`
c. `(^n C_4)/(^(^(n C_(2-n)))C_2)`
d. none of these
A. `(2^(n)C_(2))/(.^((.^(n)C_(2-n)))C_(2))`
B. `(.^(n(n-1))C_(2))/(.^((.^(n)C_(2)-n))C_(2))`
C. `(.^(n)C_(4))/(.^((.^(n)C_(2)-n))C_(2))`
D. none of these
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1 Answers
Correct Answer - C
When 4 points are selected, we get one intersecting point. So, probability is
`(.^(n)C_(4))/(.^((.^(n)C_(2)-n))C_(2))`
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Answered