A box contains 6 nails and 10 nuts. Half of the nails and half of the nuts are rusted. If one item is chosen at random, then find the probability that

Question

A box contains 6 nails and 10 nuts. Half of the nails and half of the nuts are rusted. If one item is chosen at random, then find the probability that

A box contains 6 nails and 10 nuts. Half of the nails and half of the nuts are rusted. If one item is chosen at random, then find the probability that it is rusted or is a nail.

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

The total number of nails and nuts is 6 + 10 = 16.
P(R ) = `(1)/(2)` (R stands for rusted)
P(N) = `(6)/(16)` (N stands for nails)
`P(R nn N) = (3)/(16)` [`because` 3 nails are rusted out of 6 nails]
`therefore P(R uu N) = P(R) + P(N) - P(R nn N)`
`=(1)/(2) + (6)/(16) - (3)/(16) = (8 + 6 - 3)/(16) = (11)/(16)`

4 views Answered 2023-02-05 15:29