Two identical conducting wires `AOB and COD` are placed at right angles to each other. The wire `AOB` carries an electric current `I_(1) and COD` carr

Question

Two identical conducting wires `AOB and COD` are placed at right angles to each other. The wire `AOB` carries an electric current `I_(1) and COD` carr

Two identical conducting wires `AOB and COD` are placed at right angles to each other. The wire `AOB` carries an electric current `I_(1) and COD` carries a current `I_(2)`. The magnetic field on a point lying at a distance `d` from O, in a direction perpendicular to the plane of the wires `AOB and COD`, will be given by
A. `mu_(0)/(2pi)((I_(1)+I_(2))/d)^(1//2)`
B. `mu_(0)/(2pid)(I_(1)^(2)+I_(2)^(2))^(1//2)`
C. `mu_(0)/(2pid)(I_(1)+I_(2))`
D. `mu_(0)/(2pid)(I_(1)^(2)+I_(2)^(2))`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - 2
Magnetic field due to `AB` and `CD` are `(mu_(0)I_(1))/(2pid)` and `(mu_(0)I_(2))/(2pid)`respectively
`B_("net")=mu_(0)/(2pid)sqrt(I_(1)^(2)+I_(2)^(2))`

4 views Answered 2023-02-05 15:29