A charge `Q` is spread uniformly over an insulated ring of radius `R`.What is the magnetic moment of the ring if it is rotated with an angluar velocit

Question

A charge `Q` is spread uniformly over an insulated ring of radius `R`.What is the magnetic moment of the ring if it is rotated with an angluar velocit

A charge `Q` is spread uniformly over an insulated ring of radius `R`.What is the magnetic moment of the ring if it is rotated with an angluar velocity `omega` about its axis?

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A::B
`i=Qf=(Qomega)/(2pi)`
`M=ixxpiR^(2)=(QomegaR^(2))/2`

5 views Answered 2023-02-05 15:29