Rate law for ozone layer depletion is,
`(d[O_(3)])/(dt)=(K[O_(3)]^(2))/([O_(2)])`
Give the proboble mechanism of reaction ?

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1 Answers

`O_(3)hArrO_(2)+O` (fast reaction)
`" " ` (equilibirum constant `K_(c))`
`O_(3)+Orarr2O_(2)` (slow reaction, rate constan k)
Rate `=k[O_(3)][O]" " ....(i)`
`K_(c)([O_(3)][O])/([O_(3)])or[O]=k_(c)([O_(3)])/([O_(2)])`
`" "` putting the value in eq. (i)
From eq. (i).
Rate `=k*[O_(3)]*K_(c)([O_(3)])/([O_(2)])=k*K_(c)([O_(3)]^(2))/([O_(2)])=k*([O_(3)]^(2))/([O_(2)])`
Here, `K=kxxK_(c)`

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