An object of height 3.0 cm is placed vertically on the principal axis of a convex lens. when the object distance is -37.5 cm.

Question

An object of height 3.0 cm is placed vertically on the principal axis of a convex lens. when the object distance is -37.5 cm.

An object of height 3.0 cm is placed vertically on the principal axis of a convex lens. when the object distance is -37.5 cm. an image of height -2.0 cm is formed at a distance of 25.0 cm from the lens. Next, the same object is placed vertically at 25.0 cm from the lens. In this situation the image distance v and height h of the image is (according to the new cartesian sign convention) :

(a) v = + 37.5 cm; h = + 4.5 cm

(b) v = -37.5 cm; h = + 4.5 cm

(c) v = + 37.5 cm; h = -4.5 cm

(d) v = -37.5 cm; h = -4.5 cm

Monjur Alahi

35 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct answer is (c) v = + 37.5 cm; h = -4.5 cm

In I^st case, object is beyond c, so image is at 25 cm from the lens in other side. but when object is at 25 cm, (i.e, between f and c), image will be longer and inverted (real) and beyond c, on the other side.

putting sign conventions,

v = + 37.5 cm, but h = -4.5 cm.

35 views Answered 2023-02-05 15:29