Let matrix X = [xij] is given by X = \(\begin{bmatrix} 1 &-1 &2 \\[0.3em] 3&4 & -5 \\[0.3em] 2 & -1& 3 \end{bmatrix}\). Then the matrix Y = [mij],where mij = Minor of xij is :

[(1,-1,2),(3,4,-5),(2,-1,3)]

(a) \(\begin{bmatrix} 7 &-5 &-3 \\[0.3em] 19&1 & -11 \\[0.3em] -11 & 1& 7 \end{bmatrix}\) 

(b) \(\begin{bmatrix} 7 &-19 &-11 \\[0.3em] 5&-1 & -1 \\[0.3em] 3 & 11& 7 \end{bmatrix}\) 

(c) \(\begin{bmatrix} 7 &19 &-11 \\[0.3em] -3&11 & 7 \\[0.3em] -5 & -1& -1 \end{bmatrix}\)

(d) \(\begin{bmatrix} 7 &19 &-11 \\[0.3em] -1&-1 & 1 \\[0.3em] -3 & -11& 7 \end{bmatrix}\)

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Option : (d) \(\begin{bmatrix} 7 &19 &-11 \\[0.3em] -1&-1 & 1 \\[0.3em] -3 & -11& 7 \end{bmatrix}\)

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