The slope of the line perpendicular to 13x – 7y + 1 = 0 is ……………….

The slope of the line perpendicular to 13x – 7y + 1 = 0 is ……………….

A) \(\cfrac{-7}{13}\)

B) \(\cfrac{7}{3}\)

C) \(-\cfrac{7}{3}\)

D) \(\cfrac{13}{7}\)

Monjur Alahi

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2025-01-04 04:42

0 Answers

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