For a doubly ionised Li-atom
A. Angular momentum of an electron in `3rd` orbit is `(3h)/(2pi)`
B. energy of electron in `2nd` ecited state is `-13.6 eV`.
C. Speed of electron in `3rd` orbit is `(c)/(137)`, where c is speed of light
D. Kinetic energy of electron is 2nd excited state is half of the magnitude of the potential energy.

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Correct Answer - A::B::C::D
(A) `L = (nh)/(2pi)` , (B) `E = (-13.6Z^(2))/(n^(2))`
(C ) `v = (c )/(137)(Z)/(n)` , (D) `K = -(U)/(2)`

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