The probability of nucleus to decay in two mean lives is
A. `1//4`
B. `(e^(2) - 1)/(e^(2))`
C. `3//4`
D. `1/e^(2)`

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Correct Answer - B
`P(D) = 1-e^(-lambdat) = 1 - e^(-lambdaxx 2//lambda) = (e^(2) - 1)/(e^(2))`

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