Atomic weight of a radioactive element is `M_(W)` gm. Radioactivity of m gm of its mass is :- (`N_(A) = ` Avogardro number, `lambda` = decay constant)

Atomic weight of a radioactive element is `M_(W)` gm. Radioactivity of m gm of its mass is :-
(`N_(A) = ` Avogardro number, `lambda` = decay constant)
A. `N_(A)lambda`
B. `[(N_(A))/(M_(W))m]lambda`
C. `[(N_(A))/(m)]lambda`
D. `[(N_(A))/(m)M_(w)]lambda`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - B
`R = lambdaN = lambda[(m)/(M_(w)) N_(A)]`

4 views Answered 2023-02-05 15:29

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