`""_(92)U""^(235)` nucleus absorbes a neutron and disintegrate into `""_(54)Xe""^(139),""_(38)Sr""^(94)`, and x neutrons x is

Question

`""_(92)U""^(235)` nucleus absorbes a neutron and disintegrate into `""_(54)Xe""^(139),""_(38)Sr""^(94)`, and x neutrons x is

`""_(92)U""^(235)` nucleus absorbes a neutron and disintegrate into `""_(54)Xe""^(139),""_(38)Sr""^(94)`, and x neutrons x is
A. 3-neutrons
B. 2-neutrons
C. `alpha`particle
D. `beta`particle

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`_(92)U^(256)` nucleus absorbs a neutron and then disntegratein `_(54)Xe^(139),_(38)Sr^(94)` and X.
Thus
`_(92U^(235)+_(0)n^(1)rarr_(54)Xe^(139)+_(38)Sr^(94)+3_(0)n^(1))`
Hence the product is 3 neutrons.

5 views Answered 2023-02-05 15:29