Two particles A and B are performing SHM along x and y-axis respectively with equal amplitude and frequency of `2 cm` and `1 Hz` respectively. Equilib

Question

Two particles A and B are performing SHM along x and y-axis respectively with equal amplitude and frequency of `2 cm` and `1 Hz` respectively. Equilib

Two particles A and B are performing SHM along x and y-axis respectively with equal amplitude and frequency of `2 cm` and `1 Hz` respectively. Equilibrium positions of the particles A and B are at the coordinates `[3 cm, 0]` and `(0, 4 cm)` respectively. At `t = 0 ,B` is at its equilibrium position and moving towards the origin, while A is nearest to the origin and moving away from the origin-
Equation of motion of particle B can be written as-
A. `y = (2 cm) cos 2 pit`
B. `y = (4 cm) - (2 cm) cos 2pit`
C. `y = (2 cm) sin 2 pit`
D. `y = (4 cm) - (2 cm) sin 2pit`

Monjur Alahi

15 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
As B is at its equilibrium position and moving towards negative exterme at `t = 0`
so `y-4 = 0.2 sin (2pit + pi) rArr y= 4 -2 sin (2pit)`

15 views Answered 2023-02-05 15:29