A particle executes `SHM` on a line `8` cm long. Its `K.E.` and `P.E.` will be equal when its distance from the mean position is :-

Question

A particle executes `SHM` on a line `8` cm long. Its `K.E.` and `P.E.` will be equal when its distance from the mean position is :-

A particle executes `SHM` on a line `8` cm long. Its `K.E.` and `P.E.` will be equal when its distance from the mean position is :-
A. `4 cm`
B. `2 cm`
C. `2 sqrt(2) cm`
D. `sqrt(2) cm`

Monjur Alahi

7 views

2025-01-04 04:42

1 Answers

Related Questions

The time period of a particle executing `SHM` is `T`. After a time `T//6` after it passes its mean position, then at`t = 0` its :

2 Answers 6 Views

A particle performs SHM of amplitude A along a straight line. When it is at distance `sqrt(3)/2` A from mean position, its kinetic energy gets increas

2 Answers 6 Views

A particle of mass `m` excuting `SHM` make `f` oscillation per second. The difference of its kinetic energy when at the centre, and when at distance x

2 Answers 4 Views

Passage IV) Angular frequency in SHM is given by `omega=sqrt(k/m)`. Maximum acceleration in SHM is `omega^(2)` A and maximum value of friction between

2 Answers 5 Views

A particle is executing SHM given by `x = A sin (pit + phi)`. The initial displacement of particle is `1 cm` and its initial velocity is `pi cm//sec`.

2 Answers 5 Views

At particle is executing `SHM` with amplitude `A` and has maximum velocity `v_(0)`. Find its speed when it is located at distance of `(A)/(2)` from me

2 Answers 4 Views

A particle is executing `SHM`. Find the positions of the particle where its speed is `8 cm//s`, if maximum magnitudes of its velocity and accleration

2 Answers 6 Views

A particle performing `SHM` with amplitude `10cm`. At What distance from mean position the kinetic energy of the particle is thrice of its potential e

2 Answers 10 Views

A particle performing `SHM` takes time equal to `T` (time period of `SHM`) in consecutive appearances at a perticular point. This point is :

2 Answers 5 Views

A mass `M`, attached to a horizontal spring, excutes `SHM` with a amplitude `A_(1)`. When the mass `M` passes through its mean position then a smaller

2 Answers 4 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
Here `1/2mv^(2) = 1/2kx^(2) rArr 1/2 momega^(2)(a^(2) - x^(2)) = 1/2momega^(2)x^(2)`
`rArr x = a/(sqrt(2)) = (4)/(sqrt(2)) = 2sqrt(2)cm`

7 views Answered 2023-02-05 15:29