If the radius of inner most electronic orbit of a hydrogen atom is `5.3xx10^(-11)` m, then the radii of `n=2` orbit is

Question

If the radius of inner most electronic orbit of a hydrogen atom is `5.3xx10^(-11)` m, then the radii of `n=2` orbit is

If the radius of inner most electronic orbit of a hydrogen atom is `5.3xx10^(-11)` m, then the radii of `n=2` orbit is
A. `1.12 Å`
B. `2.12 Å`
C. `3.22 Å`
D. `4.54 Å`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
As,`r_n=n^2a_0`
Here,`a_0=5.3xx10^(-11)m`,`n=2`
`therefore r_2=(2)^2a_0=4a_0=4xx5.3xx10^(-11)m`
`=21.2xx10^(-11)m=2.12Å`.

4 views Answered 2023-02-05 15:29