In order to establish an instantaneous displacemet current of 1 mA in the space between the plates of 2`mu`F parallel plate capacitor, the potential d

Question

In order to establish an instantaneous displacemet current of 1 mA in the space between the plates of 2`mu`F parallel plate capacitor, the potential d

In order to establish an instantaneous displacemet current of 1 mA in the space between the plates of 2`mu`F parallel plate capacitor, the potential difference need to apply is
A. `100 V s^(-1)`
B. `200V s^(-1)`
C. `300Vs^(-1)`
D. `500 V s^(-1)`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`I_(D)="1 mA" =10^(-3)A,C=2muF=2xx10^(-6)F`
`I_(D)=I_(C)=(d)/(dt)(CV)=C(dV)/(dt)`
Therefore, `(dV)/(dt)=(I_(D))/(C)=(10^(-3))/(2xx10^(-6))=500"V s"^(-1)`
Therefore, applying a varying potential difference of 500 V `s^(-1)` would produce a displacement current of desired value.

5 views Answered 2023-02-05 15:29