n moles of an ideal triatomic linear gas undergoes a process in which the temperature changes with volume as `T=K_(1)V^(2)` where `K_(1)` is a constan

Question

n moles of an ideal triatomic linear gas undergoes a process in which the temperature changes with volume as `T=K_(1)V^(2)` where `K_(1)` is a constan

n moles of an ideal triatomic linear gas undergoes a process in which the temperature changes with volume as `T=K_(1)V^(2)` where `K_(1)` is a constant. Choose incorrect alternative.
A. At normal temperature `C_(v)= (5)/(2)R`
B. At any temperature `C_(p)-C_(v) = R`
C. At normal temperature molar heat capacity ` C=3R`
D. At any temperature molar heat capacity `C=3R`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - A::B::C
At normal temperature `C_(v)=(f)/(2)R =(5)/(2)R` , At any temperature `C_(p) - C_(v) = ((f)/(2)+1) - (f)/(2)R = R`
from process `T= k_(1)V^(2)` ideal gas equation `PV = nRT` we have `PV^(-1)` = constant `implies x = -1`
`implies C= C_("v") + (R)/(1-"x") = C_("v")+ (R)/(1+1) = C_("v")+ (R)/(2)` At normal temperature `C = (5)/(2)R +(R)/(2) = 3R`