If P(A)=0.4,P(B)=0.8 and P(B/A)=0.6, then `P(AcupB)` is equal to
If P(A)=0.4,P(B)=0.8 and P(B/A)=0.6, then `P(AcupB)` is equal to
A. 0.24
B. 0.3
C. 0.48
D. 0.96
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Here, P(A)=0.4,P(B)=0.8andP(A/B)=0.6
`because P(B//A)=(P(BcapA))/(P(A))`
`rArr P(BcapA)=P(B//A)cdotP(A)`
`=0.6xx0.4=0.24`
`thereforeP(AcupB)=P(A)+P(B)-P(AcapB)`
`=0.4+0.8-0.24`
`=1.2-0.24=0.96`
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