If A and B are two events such that `P(A)!=0`and `P(B | A) = 1`; then(A) `AsubB` (B) `BsubA` (C) `B=varphi` (D) `A=varphi`
If A and B are two events such that `P(A)!=0`and `P(B | A) = 1`; then(A) `AsubB` (B) `BsubA` (C) `B=varphi` (D) `A=varphi`
A. `AsubB` but `A!=B`
B. `BsubA`
C. `B=phi`
D. `A=phi`
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Correct Answer - A
(a)
Given `P(A)!=0`
and `P(B/A)=1impliesP(B/A)=(P(AnnB))/(P(A))=1`
`impliesP(AnnB)=P(A)impliesAnnB=AimpliesAsubB`
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