A radioactive element X disintegrates successively `Xoverset(beta^(-))toX_(1)overset(alpha)toX_(2)overset(beta_(-))toX_(3)overset(alpha)toX_(4)` If at

Question

A radioactive element X disintegrates successively `Xoverset(beta^(-))toX_(1)overset(alpha)toX_(2)overset(beta_(-))toX_(3)overset(alpha)toX_(4)` If at

A radioactive element X disintegrates successively
`Xoverset(beta^(-))toX_(1)overset(alpha)toX_(2)overset(beta_(-))toX_(3)overset(alpha)toX_(4)`
If atomic number and atomic mass number of X are respectively, 72 and 180, then what are the corresponding values for `X_(4)` ?
A. 69172
B. 69176
C. 71176
D. `70.172`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
(d) the disintegration can be shown as below .
`""_(72)X^(180) (-2overset(-)beta )/(-2alpha )X_(4) `
Loss in atomic number `=72+2-4=70`
Loss in mass number `=180-8=172`
SO , final nucleus is `""_(70)X_(4)^(172).`

4 views Answered 2023-02-05 15:29