Consider the following statements and arrange in the order of true/false as given in the codes. `S_1:Na_2O_2ltMgOltZnOltP_4O_(10)`:Acidic property. `S

Correct Answer - C
`S_1:Na_2O_2ltMgOltZnOlt P_4O_10`: as non-metallic character increases the acidic character increases `MgO,Na_2O` are basic: ZnO amphoteric and `P_4O_10` acidic.
`S_2:NaltSigtAlltMg:Mg` has higher than Na due to small size and higher nuclear charge .Mg has highest than Al because of `ns^2` configuration (has extra stability and high electron penetration power of s-subshell electrons) and Si has highest than Al because of higher nuclear charge and small size.`IE_1 :Na=496,Al=577,Mg=737 and Si=786` kJ/mole
`S_3:`There is more interelectronic repulsion in 2p-subshell of fluorine than chlorine (3p), So extra electron will be added easily in 3p-subshell of chlorine as compared to 2p-subshell of fluorine.Down the group electron affinity values generally decreases with increasing atomic number due to increase in atomic size.
So`ClgtFgtBr`