An employee got Rs. 300 per month in his 11th year service and got ₹495 per month in his 24th year service.

Correct option is (D) ₹ 150, ₹ 15

Let initial salary of the employee be Rs a. And incriment in his salary by Rs d.

Given that his monthly salary is in A.P.

Also given that \(a_{11}=300\;\&\;a_{24}=495\)

\(\therefore a+10d=300\)      ________________(1)

& \(a+23d=495\)      ________________(2)

Subtract equation (1) from (2), we get

\(a+23d-(a+10d)=495-300\)

\(\Rightarrow13d=195\)

\(\Rightarrow d=\frac{195}{13}=15\)

\(\therefore\) Incriment is Rs 15.

Put d = 15 in equation (1), we get

\(a+150=300\)

\(\Rightarrow a=300-150=150\)

\(\therefore\) Employee's initial salary is Rs 150.

Correct option is D) ₹ 150,₹ 15