Internal Energy (E,also denoted by U):
Every system having some quantity of matter is associated with a definite amount of energy, called internal energy.
`E=E_("Transiational")+E_("Rotational")+E_("Vibrational")+E_("bonding")+`....
`DeltaE=E_("Final")-E_("initial")`
`DeltaE=q_v`, heat supplied to a gas at constant volume, since all the heat supplied goes to increase the internal energy to the gas.
It is an extensive property & a state function.It is exclusively a function of temperature.
If `DeltaT=0 , DeltaE=0` as well.
The internal energy of a certain substance is given by the following equation :
U=3 PV+84
where U is given in kJ/kg, P is in kPa, and V is in `m^3//kg`
A system composed of 3 kg of this substance expands from an initial pressure of 400 kPa and a volume of A `0.2 m^3` to a final pressure 100 kPa in a process in which pressure and volume are related by `PV^2`=constant.
If the expansion is quasi-static, then the value of q is :
A. 80 kJ
B. 60 kJ
C. 40 kJ
D. 120 kJ

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1 Answers

Correct Answer - A
U=3PV+84
`DeltaU=U_2-U_1=3(P_2V_2-P_1V_1)`
`therefore DeltaU=3(P_2V_2-P_1V_1)`
Now, `P_1V_1^2=P_2V_2^2`
`:. V_2=V_1(P_1/P_2)^(1//2)=0.2(4/1)^(1//2)=0.4`
`DeltaU=300(1xx0.4-4xx0.2)kJ = -120 kJ`
For a quasi-static process
`W=intPdV=(P_2V_2-P_1V_1)/(n-1)`
`=((1xx0.4-4xx0.2)100)/(2-1)=-40 kJ`
`:. DeltaU=q+W`
q=-120+40=-80 kJ

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