The e.m.f of a cell corresponding to the reaction `Zn+2H^(+)(aq)toZn^(2+)(0.1M)+H_(2)(g)`(1 atm) is 0.26 volt at `25^(@)C`.Calculate the pH of the sol

Question

The e.m.f of a cell corresponding to the reaction `Zn+2H^(+)(aq)toZn^(2+)(0.1M)+H_(2)(g)`(1 atm) is 0.26 volt at `25^(@)C`.Calculate the pH of the sol

The e.m.f of a cell corresponding to the reaction
`Zn+2H^(+)(aq)toZn^(2+)(0.1M)+H_(2)(g)`(1 atm)
is 0.26 volt at `25^(@)C`.Calculate the pH of the solution at the hydrogen electrode.

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - 9
`E_(cell)^@=0.76` volt
Applying nearest equation
`E_(cell)=E_(cell)^@(-0.0591)/2"log"([Zn^(2+)][P_(H_2)])/([H^+]^2), " " 0.26=0.76(-0.0591)/2"log"((0.1)(1))/([H^+]^2)`
log `0.1/([H^+]^2)=(2xx0.50)0.0591`
or log 0.1-log `[H^+]^2=17` or 2pH=17-log 0.1
pH=`18/2=9`

6 views Answered 2023-02-05 15:29