Ligth emitted during the de excitation of electrons from n=3 to n=2, when incident on metal, photoelectrons following de excitations photoelectrons ar

Question

Ligth emitted during the de excitation of electrons from n=3 to n=2, when incident on metal, photoelectrons following de excitations photoelectrons ar

Ligth emitted during the de excitation of electrons from n=3 to n=2, when incident on metal, photoelectrons following de excitations photoelectrons are just emitted from that metal. In which of the following de excitations photoelectric effect, is not possible ?
A. From n=2 to n=1
B. From n=3 to n=1
C. From n=5 to n=2
D. From n= to n=1

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - D
The photoelectric effect is possible when light of sufficient energy incident on metal surface. When electron de excites from n=3 to n=2 ,the produces photoeletrif effect. So for the given options, the photoelectric effect is not possible for that level in which energy of emitted light is less than that for n=3 to n=2
`(hv)_(4-3) lt (hv)_(3-2)`
Hence, photoelectric effect is not possible.