0.85% aqueous solution of `NaNO_(3)` is 90% dissociated at `27^(@)C`. Calculate the osmotic pressure `(R=0.082 "L atm" K^(-1) mol^(-1), d=1 "g cm"^(-3

Question

0.85% aqueous solution of `NaNO_(3)` is 90% dissociated at `27^(@)C`. Calculate the osmotic pressure `(R=0.082 "L atm" K^(-1) mol^(-1), d=1 "g cm"^(-3

0.85% aqueous solution of `NaNO_(3)` is 90% dissociated at `27^(@)C`. Calculate the osmotic pressure `(R=0.082 "L atm" K^(-1) mol^(-1), d=1 "g cm"^(-3))`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Related Questions

Osmotic pressure of naphthalene solution at `27^@C` is 500 mm Hg. When the solution is diluted and temperature is raised to `47^@C`, osmotic pressure

2 Answers 4 Views

The osmotic pressure of 0.2 molar solution of urea at `300 K(R = 0.082)` litre atm `mol^(-1)K^(-1)` is

2 Answers 5 Views

Osmotic pressure of insulin solution at 298K is found to be `0.0072` atm. Hence height of water column due to this osmotic pressure is (density of `Hg

2 Answers 6 Views

One mol an ideal gas is expanded from`(10 atm, 10lit)`. `(2 atm , 50 lit)` isothermally . First against 5 atm then against 2 atm . Calculate work done

2 Answers 6 Views

Calculate entropy charge `H_(2)O(l,1 atm, 100^(@)C)` rarr `H_(2)O(g, 1" "atm, 110^(@))` `H_(2)O(l, 2" "atm, 100^(@))`rarr `H_(2)O(g, 2" "atm, 100^(@))

2 Answers 5 Views

Calculate entropy change `H_(2) O(l, 1 atm , 100 ^(@)) to H_(2)O(g, 1 atm , 110^(@))` `H_(2) O(l, 1 atm , 100 ^(@)) to H_(2)O(g, 2 atm , 100^(@))` `De

2 Answers 4 Views

Calculate `DeltaG` for (i) `H_(2)O(l,2 atm , 300 K) to H_(2)O(g, 2 atm , 300 K ) ` (ii) `H_(2)O(l,P" "atm , 300 K) to H_(2)O(g, P" "atm , 300 K )` Cac

2 Answers 5 Views

The osmotic pressure of a solution contaiining 1.0 g protenin in 200 mL of aqueous solution at `27^(@)C` has been found to be `2.0xx10^(-1)`atm. Calcu

2 Answers 4 Views

138 gm of `N_2O_4(g)` is placed in 8.2L container at 300 K.The equilibrium vapour density of mixture was found to be 30.67.Then (R=0.082 L atm `"mol"^

2 Answers 6 Views

Two cells A and B are contiguous. Cell A has osmotic pressure 10 atm, turgor pressure-7 atm and diffusion pressure deficit 3 atm. Cell B has osmotic p

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Volume of `NaNO_(3)` solution
`=((100g))/((1"g cm"^(-3)))=100cm^(3)=0.1 L`
`NaON_(3)` dissociates as :
`NaON_(3)toNa^(+)+NO_(3)^(-)`
`alpha=((i-1))/((n-1))i.e.0.9(i-1)/(2-1)`
i-1+0.9=1.9
`M_(B)=23+14+48=85" g mol"^(-1)`
`pi=W_(B)/M_(B)xx(RxxTxxi)/V`
`=((0.85))/((85" g mol"^(-1)))`
`xx((0.082" L atm K"^(-1)"mol"^(-1))xx(300L)xx(1.0))/((0.1 L))=4.67~~5`