Two thin converging lenses are placed on a common axis, so that the centre of one of them coincides with the focus of the other. An object is placed at a distance twice the focal length from the left hand lens. Where will its image be? What is the lateral magnification? The focal of each lens is f.

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Here,`f_(1)=+5.0 cm and f_(2)=-10.0 cm`
Therefore, the combined focal length F is given by
`1/F=1/(f_(1))+1/(f_(2))=1/5.0-1/10.0=+1/10.0`
`therefore` F=+b10.0 cm
i.e., the combination behaves as a converging lens of focal length 10.0 cm.

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