if `vecE=E_(0)cos(kz)cos(omegat)hati` then `vec(B)` for electromagentic wave is

Question

if `vecE=E_(0)cos(kz)cos(omegat)hati` then `vec(B)` for electromagentic wave is

if `vecE=E_(0)cos(kz)cos(omegat)hati` then `vec(B)` for electromagentic wave is
A. The associted magnetic field is given as
`B = 1/(c) (E_(1)hati - E_(2)hatj) cos(kz - omegat)`
B. The associated magnetic field is given as
`B = 1/c (E_(1)hati - E_(2)hatj) cos (kz - omegat)`
C. The given electromagnetic field is circularly polarised.
D. The given electromagnetic wave is plane polarised.

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
Here, in electromagnetic wave, the elctric field vector is given as `E = (E_(1)hati + E_(2)hatj) cos (kz - omegat)`
Also E and B perpendicular to each other and the propagation of electromgnetic wave is perpendicular to E as well as B, so the given electromagnetic wave is plane polarised.

4 views Answered 2023-02-05 15:29